-(x+2)+3(x+2)=4-(x-1)

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Solution for -(x+2)+3(x+2)=4-(x-1) equation: 



-(x+2)+3(x+2)=4-(x-1)

We move all terms to the left:

-(x+2)+3(x+2)-(4-(x-1))=0

We multiply parentheses

-(x+2)+3x-(4-(x-1))+6=0

We get rid of parentheses

-x+3x-(4-(x-1))-2+6=0



We calculate terms in parentheses: -(4-(x-1)), so:

4-(x-1)

determiningTheFunctionDomain
-(x-1)+4

We get rid of parentheses

-x+1+4

We add all the numbers together, and all the variables

-1x+5

Back to the equation:

-(-1x+5)



We add all the numbers together, and all the variables

2x-(-1x+5)+4=0

We get rid of parentheses

2x+1x-5+4=0

We add all the numbers together, and all the variables

3x-1=0

We move all terms containing x to the left, all other terms to the right

3x=1

x=1/3

x=1/3

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