-(x+3)=1/3(9x+18)-5*

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Solution for -(x+3)=1/3(9x+18)-5* equation: 



-(x+3)=1/3(9x+18)-5*

We move all terms to the left:

-(x+3)-(1/3(9x+18)-5*)=0



Domain of the equation: 3(9x+18)-5*)!=0

x∈R



We get rid of parentheses

-x-(1/3(9x+18)-5*)-3=0

We multiply all the terms by the denominator


-x*3(9x+18)-3*3(9x+18)-5*)-(1-5*)=0

We add all the numbers together, and all the variables

-x*3(9x+18)-3*3(9x+18)-5*)-0=0

We add all the numbers together, and all the variables

-x*3(9x+18)-3*3(9x+18)=0

Wy multiply elements

-3x^2(9-9x(9=0

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