-(x+3-x=2x-7

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Solution for -(x+3-x=2x-7 equation: 



-(x+3-x=2x-7

We move all terms to the left:

-(x+3-x-(2x-7)=0



We calculate terms in parentheses: -(x+3-x-(2x-7), so:

x+3-x-(2x-7

determiningTheFunctionDomain
x-x-(2x-7+3

We add all the numbers together, and all the variables

-(2x-7+3

Back to the equation:

-(-(2x-7+3)



We add all the numbers together, and all the variables

-(-(2x-4)=0



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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





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-(2x-4





We calculate terms in parentheses: -(-(2x-4), so:

-(2x-4





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-(2x-4





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-(2x-4





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