-(x+4)+3(x-2)=-x+6+3x-10

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Solution for -(x+4)+3(x-2)=-x+6+3x-10 equation:


Simplifying
-1(x + 4) + 3(x + -2) = -1x + 6 + 3x + -10

Reorder the terms:
-1(4 + x) + 3(x + -2) = -1x + 6 + 3x + -10
(4 * -1 + x * -1) + 3(x + -2) = -1x + 6 + 3x + -10
(-4 + -1x) + 3(x + -2) = -1x + 6 + 3x + -10

Reorder the terms:
-4 + -1x + 3(-2 + x) = -1x + 6 + 3x + -10
-4 + -1x + (-2 * 3 + x * 3) = -1x + 6 + 3x + -10
-4 + -1x + (-6 + 3x) = -1x + 6 + 3x + -10

Reorder the terms:
-4 + -6 + -1x + 3x = -1x + 6 + 3x + -10

Combine like terms: -4 + -6 = -10
-10 + -1x + 3x = -1x + 6 + 3x + -10

Combine like terms: -1x + 3x = 2x
-10 + 2x = -1x + 6 + 3x + -10

Reorder the terms:
-10 + 2x = 6 + -10 + -1x + 3x

Combine like terms: 6 + -10 = -4
-10 + 2x = -4 + -1x + 3x

Combine like terms: -1x + 3x = 2x
-10 + 2x = -4 + 2x

Add '-2x' to each side of the equation.
-10 + 2x + -2x = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
-10 + 0 = -4 + 2x + -2x
-10 = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
-10 = -4 + 0
-10 = -4

Solving
-10 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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