-(x+4)+6(x-3)=x+2

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Solution for -(x+4)+6(x-3)=x+2 equation: 



-(x+4)+6(x-3)=x+2

We move all terms to the left:

-(x+4)+6(x-3)-(x+2)=0

We multiply parentheses

-(x+4)+6x-(x+2)-18=0

We get rid of parentheses

-x+6x-x-4-2-18=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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