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-(x+6)(x+4)=x(x+11+16)-
We move all terms to the left:
-(x+6)(x+4)-(x(x+11+16)-)=0
We add all the numbers together, and all the variables
-(x+6)(x+4)-(x(x+27)-)=0
We multiply parentheses ..
-(+x^2+4x+6x+24)-(x(x+27)-)=0
We calculate terms in parentheses: -(x(x+27)-), so:We get rid of parentheses
x(x+27)-
We add all the numbers together, and all the variables
x(x+27)
We multiply parentheses
x^2+27x
Back to the equation:
-(x^2+27x)
-x^2-x^2-4x-6x-27x-24=0
We add all the numbers together, and all the variables
-2x^2-37x-24=0
a = -2; b = -37; c = -24;
Δ = b2-4ac
Δ = -372-4·(-2)·(-24)
Δ = 1177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1177}}{2*-2}=\frac{37-\sqrt{1177}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1177}}{2*-2}=\frac{37+\sqrt{1177}}{-4} $
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