-(x+6)(x-4)=x(x+11+16)-

Solution for -(x+6)(x-4)=x(x+11+16)- equation:

-(x+6)(x-4)=x(x+11+16)-

We move all terms to the left:

-(x+6)(x-4)-(x(x+11+16)-)=0

We add all the numbers together, and all the variables

-(x+6)(x-4)-(x(x+27)-)=0

We multiply parentheses ..

-(+x^2-4x+6x-24)-(x(x+27)-)=0


We calculate terms in parentheses: -(x(x+27)-), so:

x(x+27)-

We add all the numbers together, and all the variables

x(x+27)

We multiply parentheses

x^2+27x

Back to the equation:

-(x^2+27x)


We get rid of parentheses

-x^2-x^2+4x-6x-27x+24=0

We add all the numbers together, and all the variables

-2x^2-29x+24=0

a = -2; b = -29; c = +24;
Δ = b2-4ac
Δ = -292-4·(-2)·24
Δ = 1033
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1033}}{2*-2}=\frac{29-\sqrt{1033}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1033}}{2*-2}=\frac{29+\sqrt{1033}}{-4}
$