-(x-1)+10=+3(x-2)

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Solution for -(x-1)+10=+3(x-2) equation: 



-(x-1)+10=+3(x-2)

We move all terms to the left:

-(x-1)+10-(+3(x-2))=0

We get rid of parentheses

-x-(+3(x-2))+1+10=0



We calculate terms in parentheses: -(+3(x-2)), so:

+3(x-2)

determiningTheFunctionDomain
3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-1x-(3x-6)+11=0

We get rid of parentheses

-1x-3x+6+11=0

We add all the numbers together, and all the variables

-4x+17=0

We move all terms containing x to the left, all other terms to the right

-4x=-17

x=-17/-4

x=4+1/4

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