-(x-1)+5=2(x+3)3x

Solution for -(x-1)+5=2(x+3)3x equation:

-(x-1)+5=2(x+3)3x

We move all terms to the left:

-(x-1)+5-(2(x+3)3x)=0

We get rid of parentheses

-x-(2(x+3)3x)+1+5=0


We calculate terms in parentheses: -(2(x+3)3x), so:

2(x+3)3x

We multiply parentheses

6x^2+18x

Back to the equation:

-(6x^2+18x)


We add all the numbers together, and all the variables

-1x-(6x^2+18x)+6=0

We get rid of parentheses

-6x^2-1x-18x+6=0

We add all the numbers together, and all the variables

-6x^2-19x+6=0

a = -6; b = -19; c = +6;
Δ = b2-4ac
Δ = -192-4·(-6)·6
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{505}}{2*-6}=\frac{19-\sqrt{505}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{505}}{2*-6}=\frac{19+\sqrt{505}}{-12}
$