-(x-1)-(3x-2)=6+2(x-1)

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Solution for -(x-1)-(3x-2)=6+2(x-1) equation: 



-(x-1)-(3x-2)=6+2(x-1)

We move all terms to the left:

-(x-1)-(3x-2)-(6+2(x-1))=0

We get rid of parentheses

-x-3x-(6+2(x-1))+1+2=0



We calculate terms in parentheses: -(6+2(x-1)), so:

6+2(x-1)

determiningTheFunctionDomain
2(x-1)+6

We multiply parentheses

2x-2+6

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

-4x-(2x+4)+3=0

We get rid of parentheses

-4x-2x-4+3=0

We add all the numbers together, and all the variables

-6x-1=0

We move all terms containing x to the left, all other terms to the right

-6x=1

x=1/-6

x=-1/6

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