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-(x-1/2)+1=2(3/2x-6)+1
We move all terms to the left:
-(x-1/2)+1-(2(3/2x-6)+1)=0
Domain of the equation: 2x-6)+1)!=0We add all the numbers together, and all the variables
x∈R
-(+x-1/2)-(2(3/2x-6)+1)+1=0
We get rid of parentheses
-x-(2(3/2x-6)+1)+1+1/2=0
We calculate fractions
-x+1=0
We add all the numbers together, and all the variables
-1x+1=0
We move all terms containing x to the left, all other terms to the right
-x=-1
x=-1/-1
x=1
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