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-(x-2)+(2x-1)=-(x+1)+2(x-1)
We move all terms to the left:
-(x-2)+(2x-1)-(-(x+1)+2(x-1))=0
We get rid of parentheses
-x+2x-(-(x+1)+2(x-1))+2-1=0
We calculate terms in parentheses: -(-(x+1)+2(x-1)), so:We add all the numbers together, and all the variables
-(x+1)+2(x-1)
We multiply parentheses
-(x+1)+2x-2
We get rid of parentheses
-x+2x-1-2
We add all the numbers together, and all the variables
x-3
Back to the equation:
-(x-3)
x-(x-3)+1=0
We get rid of parentheses
x-x+3+1=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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