-(x-2)+10(x-8)=3

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Solution for -(x-2)+10(x-8)=3 equation: 



-(x-2)+10(x-8)=3

We move all terms to the left:

-(x-2)+10(x-8)-(3)=0

We multiply parentheses

-(x-2)+10x-80-3=0

We get rid of parentheses

-x+10x+2-80-3=0

We add all the numbers together, and all the variables

9x-81=0

We move all terms containing x to the left, all other terms to the right

9x=81

x=81/9

x=9

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