-(x-2)+2=3x+4(1-x)

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Solution for -(x-2)+2=3x+4(1-x) equation: 



-(x-2)+2=3x+4(1-x)

We move all terms to the left:

-(x-2)+2-(3x+4(1-x))=0

We add all the numbers together, and all the variables

-(x-2)-(3x+4(-1x+1))+2=0

We get rid of parentheses

-x-(3x+4(-1x+1))+2+2=0



We calculate terms in parentheses: -(3x+4(-1x+1)), so:

3x+4(-1x+1)

We multiply parentheses

3x-4x+4

We add all the numbers together, and all the variables

-1x+4

Back to the equation:

-(-1x+4)



We add all the numbers together, and all the variables

-1x-(-1x+4)+4=0

We get rid of parentheses

-1x+1x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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