-(x-2)+2=3x+4(1-x)

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Solution for -(x-2)+2=3x+4(1-x) equation:



-(x-2)+2=3x+4(1-x)
We move all terms to the left:
-(x-2)+2-(3x+4(1-x))=0
We add all the numbers together, and all the variables
-(x-2)-(3x+4(-1x+1))+2=0
We get rid of parentheses
-x-(3x+4(-1x+1))+2+2=0
We calculate terms in parentheses: -(3x+4(-1x+1)), so:
3x+4(-1x+1)
We multiply parentheses
3x-4x+4
We add all the numbers together, and all the variables
-1x+4
Back to the equation:
-(-1x+4)
We add all the numbers together, and all the variables
-1x-(-1x+4)+4=0
We get rid of parentheses
-1x+1x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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