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-(x-3)+10+3x=3x+18-5-x
We move all terms to the left:
-(x-3)+10+3x-(3x+18-5-x)=0
We add all the numbers together, and all the variables
-(x-3)+3x-(2x+13)+10=0
We add all the numbers together, and all the variables
3x-(x-3)-(2x+13)+10=0
We get rid of parentheses
3x-x-2x+3-13+10=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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