-(x-3)+5-2(x+5)=3+2(5x-1)

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Solution for -(x-3)+5-2(x+5)=3+2(5x-1) equation:



-(x-3)+5-2(x+5)=3+2(5x-1)
We move all terms to the left:
-(x-3)+5-2(x+5)-(3+2(5x-1))=0
We multiply parentheses
-(x-3)-2x-(3+2(5x-1))-10+5=0
We get rid of parentheses
-x-2x-(3+2(5x-1))+3-10+5=0
We calculate terms in parentheses: -(3+2(5x-1)), so:
3+2(5x-1)
determiningTheFunctionDomain 2(5x-1)+3
We multiply parentheses
10x-2+3
We add all the numbers together, and all the variables
10x+1
Back to the equation:
-(10x+1)
We add all the numbers together, and all the variables
-3x-(10x+1)-2=0
We get rid of parentheses
-3x-10x-1-2=0
We add all the numbers together, and all the variables
-13x-3=0
We move all terms containing x to the left, all other terms to the right
-13x=3
x=3/-13
x=-3/13

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