-(x-3)+5-2(x+5)=3+2(5x-1)

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Solution for -(x-3)+5-2(x+5)=3+2(5x-1) equation: 



-(x-3)+5-2(x+5)=3+2(5x-1)

We move all terms to the left:

-(x-3)+5-2(x+5)-(3+2(5x-1))=0

We multiply parentheses

-(x-3)-2x-(3+2(5x-1))-10+5=0

We get rid of parentheses

-x-2x-(3+2(5x-1))+3-10+5=0



We calculate terms in parentheses: -(3+2(5x-1)), so:

3+2(5x-1)

determiningTheFunctionDomain
2(5x-1)+3

We multiply parentheses

10x-2+3

We add all the numbers together, and all the variables

10x+1

Back to the equation:

-(10x+1)



We add all the numbers together, and all the variables

-3x-(10x+1)-2=0

We get rid of parentheses

-3x-10x-1-2=0

We add all the numbers together, and all the variables

-13x-3=0

We move all terms containing x to the left, all other terms to the right

-13x=3

x=3/-13

x=-3/13

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