-(x-3)=2(3-x)-5

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Solution for -(x-3)=2(3-x)-5 equation: 



-(x-3)=2(3-x)-5

We move all terms to the left:

-(x-3)-(2(3-x)-5)=0

We add all the numbers together, and all the variables

-(x-3)-(2(-1x+3)-5)=0

We get rid of parentheses

-x-(2(-1x+3)-5)+3=0



We calculate terms in parentheses: -(2(-1x+3)-5), so:

2(-1x+3)-5

We multiply parentheses

-2x+6-5

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

-1x-(-2x+1)+3=0

We get rid of parentheses

-1x+2x-1+3=0

We add all the numbers together, and all the variables

x+2=0

We move all terms containing x to the left, all other terms to the right

x=-2

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