-(x-4)+2(4x-3)=5

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Solution for -(x-4)+2(4x-3)=5 equation: 



-(x-4)+2(4x-3)=5

We move all terms to the left:

-(x-4)+2(4x-3)-(5)=0

We multiply parentheses

-(x-4)+8x-6-5=0

We get rid of parentheses

-x+8x+4-6-5=0

We add all the numbers together, and all the variables

7x-7=0

We move all terms containing x to the left, all other terms to the right

7x=7

x=7/7

x=1

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