-(x-4)+2=3(x-1)

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Solution for -(x-4)+2=3(x-1) equation: 



-(x-4)+2=3(x-1)

We move all terms to the left:

-(x-4)+2-(3(x-1))=0

We get rid of parentheses

-x-(3(x-1))+4+2=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

-1x-(3x-3)+6=0

We get rid of parentheses

-1x-3x+3+6=0

We add all the numbers together, and all the variables

-4x+9=0

We move all terms containing x to the left, all other terms to the right

-4x=-9

x=-9/-4

x=2+1/4

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