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-(x-4)+5(2x+1)=4(2x-2)+14
We move all terms to the left:
-(x-4)+5(2x+1)-(4(2x-2)+14)=0
We multiply parentheses
-(x-4)+10x-(4(2x-2)+14)+5=0
We get rid of parentheses
-x+10x-(4(2x-2)+14)+4+5=0
We calculate terms in parentheses: -(4(2x-2)+14), so:We add all the numbers together, and all the variables
4(2x-2)+14
We multiply parentheses
8x-8+14
We add all the numbers together, and all the variables
8x+6
Back to the equation:
-(8x+6)
9x-(8x+6)+9=0
We get rid of parentheses
9x-8x-6+9=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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