-(x-4)=2x-5x(x+2)

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Solution for -(x-4)=2x-5x(x+2) equation:



-(x-4)=2x-5x(x+2)
We move all terms to the left:
-(x-4)-(2x-5x(x+2))=0
We get rid of parentheses
-x-(2x-5x(x+2))+4=0
We calculate terms in parentheses: -(2x-5x(x+2)), so:
2x-5x(x+2)
We multiply parentheses
-5x^2+2x-10x
We add all the numbers together, and all the variables
-5x^2-8x
Back to the equation:
-(-5x^2-8x)
We add all the numbers together, and all the variables
-(-5x^2-8x)-1x+4=0
We get rid of parentheses
5x^2+8x-1x+4=0
We add all the numbers together, and all the variables
5x^2+7x+4=0
a = 5; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·5·4
Δ = -31
Delta is less than zero, so there is no solution for the equation

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