-(x-4)=2x-5x(x+2)

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Solution for -(x-4)=2x-5x(x+2) equation: 



-(x-4)=2x-5x(x+2)

We move all terms to the left:

-(x-4)-(2x-5x(x+2))=0

We get rid of parentheses

-x-(2x-5x(x+2))+4=0



We calculate terms in parentheses: -(2x-5x(x+2)), so:

2x-5x(x+2)

We multiply parentheses

-5x^2+2x-10x

We add all the numbers together, and all the variables

-5x^2-8x

Back to the equation:

-(-5x^2-8x)



We add all the numbers together, and all the variables

-(-5x^2-8x)-1x+4=0

We get rid of parentheses

5x^2+8x-1x+4=0

We add all the numbers together, and all the variables

5x^2+7x+4=0

a = 5; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·5·4
Δ = -31
Delta is less than zero, so there is no solution for the equation

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