-(x-4)=3x+19+x

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Solution for -(x-4)=3x+19+x equation: 



-(x-4)=3x+19+x

We move all terms to the left:

-(x-4)-(3x+19+x)=0

We add all the numbers together, and all the variables

-(x-4)-(4x+19)=0

We get rid of parentheses

-x-4x+4-19=0

We add all the numbers together, and all the variables

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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