-(x-5)+3(x+1)=-2(x-9)+30

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Solution for -(x-5)+3(x+1)=-2(x-9)+30 equation: 



-(x-5)+3(x+1)=-2(x-9)+30

We move all terms to the left:

-(x-5)+3(x+1)-(-2(x-9)+30)=0

We multiply parentheses

-(x-5)+3x-(-2(x-9)+30)+3=0

We get rid of parentheses

-x+3x-(-2(x-9)+30)+5+3=0



We calculate terms in parentheses: -(-2(x-9)+30), so:

-2(x-9)+30

We multiply parentheses

-2x+18+30

We add all the numbers together, and all the variables

-2x+48

Back to the equation:

-(-2x+48)



We add all the numbers together, and all the variables

2x-(-2x+48)+8=0

We get rid of parentheses

2x+2x-48+8=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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