-(x-8)+4x=2(-x)+x

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Solution for -(x-8)+4x=2(-x)+x equation: 



-(x-8)+4x=2(-x)+x

We move all terms to the left:

-(x-8)+4x-(2(-x)+x)=0

We add all the numbers together, and all the variables

-(x-8)+4x-(2(-1x)+x)=0

We add all the numbers together, and all the variables

4x-(x-8)-(2(-1x)+x)=0

We get rid of parentheses

4x-x-(2(-1x)+x)+8=0



We calculate terms in parentheses: -(2(-1x)+x), so:

2(-1x)+x

We add all the numbers together, and all the variables

x+2(-1x)

We multiply parentheses

x-2x

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

4x-x-(-1x)+8=0

We add all the numbers together, and all the variables

3x-(-1x)+8=0

We get rid of parentheses

3x+1x+8=0

We add all the numbers together, and all the variables

4x+8=0

We move all terms containing x to the left, all other terms to the right

4x=-8

x=-8/4

x=-2

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