-(x-8)+4x=2(-x+4)+x

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Solution for -(x-8)+4x=2(-x+4)+x equation: 



-(x-8)+4x=2(-x+4)+x

We move all terms to the left:

-(x-8)+4x-(2(-x+4)+x)=0

We add all the numbers together, and all the variables

-(x-8)+4x-(2(-1x+4)+x)=0

We add all the numbers together, and all the variables

4x-(x-8)-(2(-1x+4)+x)=0

We get rid of parentheses

4x-x-(2(-1x+4)+x)+8=0



We calculate terms in parentheses: -(2(-1x+4)+x), so:

2(-1x+4)+x

We add all the numbers together, and all the variables

x+2(-1x+4)

We multiply parentheses

x-2x+8

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

3x-(-1x+8)+8=0

We get rid of parentheses

3x+1x-8+8=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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