-(x-8)+4x=2(2x-4)+x

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Solution for -(x-8)+4x=2(2x-4)+x equation: 



-(x-8)+4x=2(2x-4)+x

We move all terms to the left:

-(x-8)+4x-(2(2x-4)+x)=0

We add all the numbers together, and all the variables

4x-(x-8)-(2(2x-4)+x)=0

We get rid of parentheses

4x-x-(2(2x-4)+x)+8=0



We calculate terms in parentheses: -(2(2x-4)+x), so:

2(2x-4)+x

We add all the numbers together, and all the variables

x+2(2x-4)

We multiply parentheses

x+4x-8

We add all the numbers together, and all the variables

5x-8

Back to the equation:

-(5x-8)



We add all the numbers together, and all the variables

3x-(5x-8)+8=0

We get rid of parentheses

3x-5x+8+8=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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