-(x-8)+4x=2(x-4)+x

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Solution for -(x-8)+4x=2(x-4)+x equation:



-(x-8)+4x=2(x-4)+x
We move all terms to the left:
-(x-8)+4x-(2(x-4)+x)=0
We add all the numbers together, and all the variables
4x-(x-8)-(2(x-4)+x)=0
We get rid of parentheses
4x-x-(2(x-4)+x)+8=0
We calculate terms in parentheses: -(2(x-4)+x), so:
2(x-4)+x
We add all the numbers together, and all the variables
x+2(x-4)
We multiply parentheses
x+2x-8
We add all the numbers together, and all the variables
3x-8
Back to the equation:
-(3x-8)
We add all the numbers together, and all the variables
3x-(3x-8)+8=0
We get rid of parentheses
3x-3x+8+8=0
We add all the numbers together, and all the variables
16!=0
There is no solution for this equation

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