-(x/3)-((1/4)x)=14

Solution for -(x/3)-((1/4)x)=14 equation:

-(x/3)-((1/4)x)=14

We move all terms to the left:

-(x/3)-((1/4)x)-(14)=0


Domain of the equation: 4)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(+x/3)-((+1/4)x)-14=0

We get rid of parentheses

-x/3-((+1/4)x)-14=0

We calculate fractions


(-4x^2)/12x+()/12x-14=0

We multiply all the terms by the denominator


(-4x^2)-14*12x+()=0

We add all the numbers together, and all the variables

(-4x^2)-14*12x=0

Wy multiply elements

(-4x^2)-168x=0

We get rid of parentheses

-4x^2-168x=0

a = -4; b = -168; c = 0;
Δ = b2-4ac
Δ = -1682-4·(-4)·0
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-168}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+168}{2*-4}=\frac{336}{-8}
=-42
$