-(y+4)+3y=3(y-5)

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Solution for -(y+4)+3y=3(y-5) equation:



-(y+4)+3y=3(y-5)
We move all terms to the left:
-(y+4)+3y-(3(y-5))=0
We add all the numbers together, and all the variables
3y-(y+4)-(3(y-5))=0
We get rid of parentheses
3y-y-(3(y-5))-4=0
We calculate terms in parentheses: -(3(y-5)), so:
3(y-5)
We multiply parentheses
3y-15
Back to the equation:
-(3y-15)
We add all the numbers together, and all the variables
2y-(3y-15)-4=0
We get rid of parentheses
2y-3y+15-4=0
We add all the numbers together, and all the variables
-1y+11=0
We move all terms containing y to the left, all other terms to the right
-y=-11
y=-11/-1
y=+11

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