-(y+4)+3y=3(y-5)

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Solution for -(y+4)+3y=3(y-5) equation: 



-(y+4)+3y=3(y-5)

We move all terms to the left:

-(y+4)+3y-(3(y-5))=0

We add all the numbers together, and all the variables

3y-(y+4)-(3(y-5))=0

We get rid of parentheses

3y-y-(3(y-5))-4=0



We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)



We add all the numbers together, and all the variables

2y-(3y-15)-4=0

We get rid of parentheses

2y-3y+15-4=0

We add all the numbers together, and all the variables

-1y+11=0

We move all terms containing y to the left, all other terms to the right

-y=-11

y=-11/-1

y=+11

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