-(y-2)+3y=4(y+1)

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Solution for -(y-2)+3y=4(y+1) equation: 



-(y-2)+3y=4(y+1)

We move all terms to the left:

-(y-2)+3y-(4(y+1))=0

We add all the numbers together, and all the variables

3y-(y-2)-(4(y+1))=0

We get rid of parentheses

3y-y-(4(y+1))+2=0



We calculate terms in parentheses: -(4(y+1)), so:

4(y+1)

We multiply parentheses

4y+4

Back to the equation:

-(4y+4)



We add all the numbers together, and all the variables

2y-(4y+4)+2=0

We get rid of parentheses

2y-4y-4+2=0

We add all the numbers together, and all the variables

-2y-2=0

We move all terms containing y to the left, all other terms to the right

-2y=2

y=2/-2

y=-1

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