-(y-2)+3y=4(y+1)

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Solution for -(y-2)+3y=4(y+1) equation:



-(y-2)+3y=4(y+1)
We move all terms to the left:
-(y-2)+3y-(4(y+1))=0
We add all the numbers together, and all the variables
3y-(y-2)-(4(y+1))=0
We get rid of parentheses
3y-y-(4(y+1))+2=0
We calculate terms in parentheses: -(4(y+1)), so:
4(y+1)
We multiply parentheses
4y+4
Back to the equation:
-(4y+4)
We add all the numbers together, and all the variables
2y-(4y+4)+2=0
We get rid of parentheses
2y-4y-4+2=0
We add all the numbers together, and all the variables
-2y-2=0
We move all terms containing y to the left, all other terms to the right
-2y=2
y=2/-2
y=-1

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