-(y-3)=2y+3-3y

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Solution for -(y-3)=2y+3-3y equation:


Simplifying
-1(y + -3) = 2y + 3 + -3y

Reorder the terms:
-1(-3 + y) = 2y + 3 + -3y
(-3 * -1 + y * -1) = 2y + 3 + -3y
(3 + -1y) = 2y + 3 + -3y

Reorder the terms:
3 + -1y = 3 + 2y + -3y

Combine like terms: 2y + -3y = -1y
3 + -1y = 3 + -1y

Add '-3' to each side of the equation.
3 + -3 + -1y = 3 + -3 + -1y

Combine like terms: 3 + -3 = 0
0 + -1y = 3 + -3 + -1y
-1y = 3 + -3 + -1y

Combine like terms: 3 + -3 = 0
-1y = 0 + -1y
-1y = -1y

Add 'y' to each side of the equation.
-1y + y = -1y + y

Combine like terms: -1y + y = 0
0 = -1y + y

Combine like terms: -1y + y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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