-(z+1)+(3z+1)=-3(z+1)

Solution for -(z+1)+(3z+1)=-3(z+1) equation:

Simplifying
-1(z + 1) + (3z + 1) = -3(z + 1)

Reorder the terms:
-1(1 + z) + (3z + 1) = -3(z + 1)
(1 * -1 + z * -1) + (3z + 1) = -3(z + 1)
(-1 + -1z) + (3z + 1) = -3(z + 1)

Reorder the terms:
-1 + -1z + (1 + 3z) = -3(z + 1)

Remove parenthesis around (1 + 3z)
-1 + -1z + 1 + 3z = -3(z + 1)

Reorder the terms:
-1 + 1 + -1z + 3z = -3(z + 1)

Combine like terms: -1 + 1 = 0
0 + -1z + 3z = -3(z + 1)
-1z + 3z = -3(z + 1)

Combine like terms: -1z + 3z = 2z
2z = -3(z + 1)

Reorder the terms:
2z = -3(1 + z)
2z = (1 * -3 + z * -3)
2z = (-3 + -3z)

Solving
2z = -3 + -3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '3z' to each side of the equation.
2z + 3z = -3 + -3z + 3z

Combine like terms: 2z + 3z = 5z
5z = -3 + -3z + 3z

Combine like terms: -3z + 3z = 0
5z = -3 + 0
5z = -3

Divide each side by '5'.
z = -0.6

Simplifying
z = -0.6