-(z+1)+2(2-2)=

Solution for -(z+1)+2(2-2)= equation:

Simplifying
-1(z + 1) + 2(2 + -2) = 0

Reorder the terms:
-1(1 + z) + 2(2 + -2) = 0
(1 * -1 + z * -1) + 2(2 + -2) = 0
(-1 + -1z) + 2(2 + -2) = 0

Combine like terms: 2 + -2 = 0
-1 + -1z + 2(0) = 0

Multiply 2 * 0
-1 + -1z + 0 = 0

Anything times zero is zero.
-1 + -1z + 0 = 0

Reorder the terms:
-1 + 0 + -1z = 0

Combine like terms: -1 + 0 = -1
-1 + -1z = 0

Solving
-1 + -1z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1z = 0 + 1
-1z = 0 + 1

Combine like terms: 0 + 1 = 1
-1z = 1

Divide each side by '-1'.
z = -1

Simplifying
z = -1