-(z+1)=2(z-1)

Solution for -(z+1)=2(z-1) equation:

-(z+1)=2(z-1)

We move all terms to the left:

-(z+1)-(2(z-1))=0

We get rid of parentheses

-z-(2(z-1))-1=0


We calculate terms in parentheses: -(2(z-1)), so:

2(z-1)

We multiply parentheses

2z-2

Back to the equation:

-(2z-2)


We add all the numbers together, and all the variables

-1z-(2z-2)-1=0

We get rid of parentheses

-1z-2z+2-1=0

We add all the numbers together, and all the variables

-3z+1=0

We move all terms containing z to the left, all other terms to the right

-3z=-1

z=-1/-3

z=1/3