-(z+2)-2(1-z)=

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Solution for -(z+2)-2(1-z)= equation:


Simplifying
-1(z + 2) + -2(1 + -1z) = 0

Reorder the terms:
-1(2 + z) + -2(1 + -1z) = 0
(2 * -1 + z * -1) + -2(1 + -1z) = 0
(-2 + -1z) + -2(1 + -1z) = 0
-2 + -1z + (1 * -2 + -1z * -2) = 0
-2 + -1z + (-2 + 2z) = 0

Reorder the terms:
-2 + -2 + -1z + 2z = 0

Combine like terms: -2 + -2 = -4
-4 + -1z + 2z = 0

Combine like terms: -1z + 2z = 1z
-4 + 1z = 0

Solving
-4 + 1z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1z = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 1z = 0 + 4
1z = 0 + 4

Combine like terms: 0 + 4 = 4
1z = 4

Divide each side by '1'.
z = 4

Simplifying
z = 4

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