-(z+4)+(3z+1)=-2(z+1)

Solution for -(z+4)+(3z+1)=-2(z+1) equation:

Simplifying
-1(z + 4) + (3z + 1) = -2(z + 1)

Reorder the terms:
-1(4 + z) + (3z + 1) = -2(z + 1)
(4 * -1 + z * -1) + (3z + 1) = -2(z + 1)
(-4 + -1z) + (3z + 1) = -2(z + 1)

Reorder the terms:
-4 + -1z + (1 + 3z) = -2(z + 1)

Remove parenthesis around (1 + 3z)
-4 + -1z + 1 + 3z = -2(z + 1)

Reorder the terms:
-4 + 1 + -1z + 3z = -2(z + 1)

Combine like terms: -4 + 1 = -3
-3 + -1z + 3z = -2(z + 1)

Combine like terms: -1z + 3z = 2z
-3 + 2z = -2(z + 1)

Reorder the terms:
-3 + 2z = -2(1 + z)
-3 + 2z = (1 * -2 + z * -2)
-3 + 2z = (-2 + -2z)

Solving
-3 + 2z = -2 + -2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '2z' to each side of the equation.
-3 + 2z + 2z = -2 + -2z + 2z

Combine like terms: 2z + 2z = 4z
-3 + 4z = -2 + -2z + 2z

Combine like terms: -2z + 2z = 0
-3 + 4z = -2 + 0
-3 + 4z = -2

Add '3' to each side of the equation.
-3 + 3 + 4z = -2 + 3

Combine like terms: -3 + 3 = 0
0 + 4z = -2 + 3
4z = -2 + 3

Combine like terms: -2 + 3 = 1
4z = 1

Divide each side by '4'.
z = 0.25

Simplifying
z = 0.25