-(z+4)+(6z+1)=2(z+1)

Solution for -(z+4)+(6z+1)=2(z+1) equation:

Simplifying
-1(z + 4) + (6z + 1) = 2(z + 1)

Reorder the terms:
-1(4 + z) + (6z + 1) = 2(z + 1)
(4 * -1 + z * -1) + (6z + 1) = 2(z + 1)
(-4 + -1z) + (6z + 1) = 2(z + 1)

Reorder the terms:
-4 + -1z + (1 + 6z) = 2(z + 1)

Remove parenthesis around (1 + 6z)
-4 + -1z + 1 + 6z = 2(z + 1)

Reorder the terms:
-4 + 1 + -1z + 6z = 2(z + 1)

Combine like terms: -4 + 1 = -3
-3 + -1z + 6z = 2(z + 1)

Combine like terms: -1z + 6z = 5z
-3 + 5z = 2(z + 1)

Reorder the terms:
-3 + 5z = 2(1 + z)
-3 + 5z = (1 * 2 + z * 2)
-3 + 5z = (2 + 2z)

Solving
-3 + 5z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-3 + 5z + -2z = 2 + 2z + -2z

Combine like terms: 5z + -2z = 3z
-3 + 3z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-3 + 3z = 2 + 0
-3 + 3z = 2

Add '3' to each side of the equation.
-3 + 3 + 3z = 2 + 3

Combine like terms: -3 + 3 = 0
0 + 3z = 2 + 3
3z = 2 + 3

Combine like terms: 2 + 3 = 5
3z = 5

Divide each side by '3'.
z = 1.666666667

Simplifying
z = 1.666666667