-(z+5)+(4z+1)=3(z+1)

Solution for -(z+5)+(4z+1)=3(z+1) equation:

Simplifying
-1(z + 5) + (4z + 1) = 3(z + 1)

Reorder the terms:
-1(5 + z) + (4z + 1) = 3(z + 1)
(5 * -1 + z * -1) + (4z + 1) = 3(z + 1)
(-5 + -1z) + (4z + 1) = 3(z + 1)

Reorder the terms:
-5 + -1z + (1 + 4z) = 3(z + 1)

Remove parenthesis around (1 + 4z)
-5 + -1z + 1 + 4z = 3(z + 1)

Reorder the terms:
-5 + 1 + -1z + 4z = 3(z + 1)

Combine like terms: -5 + 1 = -4
-4 + -1z + 4z = 3(z + 1)

Combine like terms: -1z + 4z = 3z
-4 + 3z = 3(z + 1)

Reorder the terms:
-4 + 3z = 3(1 + z)
-4 + 3z = (1 * 3 + z * 3)
-4 + 3z = (3 + 3z)

Add '-3z' to each side of the equation.
-4 + 3z + -3z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-4 + 0 = 3 + 3z + -3z
-4 = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-4 = 3 + 0
-4 = 3

Solving
-4 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.