-(z+9)+(2z+1)=4(z+1)

Solution for -(z+9)+(2z+1)=4(z+1) equation:

Simplifying
-1(z + 9) + (2z + 1) = 4(z + 1)

Reorder the terms:
-1(9 + z) + (2z + 1) = 4(z + 1)
(9 * -1 + z * -1) + (2z + 1) = 4(z + 1)
(-9 + -1z) + (2z + 1) = 4(z + 1)

Reorder the terms:
-9 + -1z + (1 + 2z) = 4(z + 1)

Remove parenthesis around (1 + 2z)
-9 + -1z + 1 + 2z = 4(z + 1)

Reorder the terms:
-9 + 1 + -1z + 2z = 4(z + 1)

Combine like terms: -9 + 1 = -8
-8 + -1z + 2z = 4(z + 1)

Combine like terms: -1z + 2z = 1z
-8 + 1z = 4(z + 1)

Reorder the terms:
-8 + 1z = 4(1 + z)
-8 + 1z = (1 * 4 + z * 4)
-8 + 1z = (4 + 4z)

Solving
-8 + 1z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-8 + 1z + -4z = 4 + 4z + -4z

Combine like terms: 1z + -4z = -3z
-8 + -3z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-8 + -3z = 4 + 0
-8 + -3z = 4

Add '8' to each side of the equation.
-8 + 8 + -3z = 4 + 8

Combine like terms: -8 + 8 = 0
0 + -3z = 4 + 8
-3z = 4 + 8

Combine like terms: 4 + 8 = 12
-3z = 12

Divide each side by '-3'.
z = -4

Simplifying
z = -4