--(8n-2)=3+10(1-3n)

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Solution for --(8n-2)=3+10(1-3n) equation: 



--(8n-2)=3+10(1-3n)

We move all terms to the left:

--(8n-2)-(3+10(1-3n))=0

We add all the numbers together, and all the variables

-(8n-2)-(3+10(-3n+1))-=0

We add all the numbers together, and all the variables

-(8n-2)-(3+10(-3n+1))=0

We get rid of parentheses

-8n-(3+10(-3n+1))+2=0



We calculate terms in parentheses: -(3+10(-3n+1)), so:

3+10(-3n+1)

determiningTheFunctionDomain
10(-3n+1)+3

We multiply parentheses

-30n+10+3

We add all the numbers together, and all the variables

-30n+13

Back to the equation:

-(-30n+13)



We get rid of parentheses

-8n+30n-13+2=0

We add all the numbers together, and all the variables

22n-11=0

We move all terms containing n to the left, all other terms to the right

22n=11

n=11/22

n=1/2

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