---------------------------6=n/2-10

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Solution for ---------------------------6=n/2-10 equation: 


(e^(2*x+1)*(2*x^2-(10*x)+3))/((x-2)^3) = 0

13;24;1;8;3;1

27;26;5;9;0;0

1;2;1;8;0;0

(e^(2*x+1)*(2*x-5))/((x-2)^2) = 0

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