--10y+18=3(5y-7)+5y

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Solution for --10y+18=3(5y-7)+5y equation: 



--10y+18=3(5y-7)+5y

We move all terms to the left:

--10y+18-(3(5y-7)+5y)=0

We add all the numbers together, and all the variables

-10y-(3(5y-7)+5y)=0



We calculate terms in parentheses: -(3(5y-7)+5y), so:

3(5y-7)+5y

We add all the numbers together, and all the variables

5y+3(5y-7)

We multiply parentheses

5y+15y-21

We add all the numbers together, and all the variables

20y-21

Back to the equation:

-(20y-21)



We get rid of parentheses

-10y-20y+21=0

We add all the numbers together, and all the variables

-30y+21=0

We move all terms containing y to the left, all other terms to the right

-30y=-21

y=-21/-30

y=7/10

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