--10y+18=3(5y-7)+5y

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Solution for --10y+18=3(5y-7)+5y equation:



--10y+18=3(5y-7)+5y
We move all terms to the left:
--10y+18-(3(5y-7)+5y)=0
We add all the numbers together, and all the variables
-10y-(3(5y-7)+5y)=0
We calculate terms in parentheses: -(3(5y-7)+5y), so:
3(5y-7)+5y
We add all the numbers together, and all the variables
5y+3(5y-7)
We multiply parentheses
5y+15y-21
We add all the numbers together, and all the variables
20y-21
Back to the equation:
-(20y-21)
We get rid of parentheses
-10y-20y+21=0
We add all the numbers together, and all the variables
-30y+21=0
We move all terms containing y to the left, all other terms to the right
-30y=-21
y=-21/-30
y=7/10

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