--2(x+3)+5(x-2)=2

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Solution for --2(x+3)+5(x-2)=2 equation:



--2(x+3)+5(x-2)=2
We move all terms to the left:
--2(x+3)+5(x-2)-(2)=0
determiningTheFunctionDomain -2(x+3)+5(x-2)-2-=0
We add all the numbers together, and all the variables
-2(x+3)+5(x-2)=0
We multiply parentheses
-2x+5x-6-10=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3

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