-.4y-2(3-5y)+2=-3y-0.5(-3-2y)

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Solution for -.4y-2(3-5y)+2=-3y-0.5(-3-2y) equation: 



-.4y-2(3-5y)+2=-3y-0.5(-3-2y)

We move all terms to the left:

-.4y-2(3-5y)+2-(-3y-0.5(-3-2y))=0

We add all the numbers together, and all the variables

-.4y-2(-5y+3)-(-3y-0.5(-2y-3))+2=0

We add all the numbers together, and all the variables

-0.4y-2(-5y+3)-(-3y-0.5(-2y-3))+2=0

We multiply parentheses

-0.4y+10y-(-3y-0.5(-2y-3))-6+2=0



We calculate terms in parentheses: -(-3y-0.5(-2y-3)), so:

-3y-0.5(-2y-3)

We multiply parentheses

-3y+1y+1.5

We add all the numbers together, and all the variables

-2y+1.5

Back to the equation:

-(-2y+1.5)



We add all the numbers together, and all the variables

9.6y-(-2y+1.5)-4=0

We get rid of parentheses

9.6y+2y-1.5-4=0

We add all the numbers together, and all the variables

11.6y-5.5=0

We move all terms containing y to the left, all other terms to the right

11.6y=5.5

y=5.5/11.6

y=3.66666666667/7.73333333333

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