-/12z=27/20

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Solution for -/12z=27/20 equation: 



-/12z=27/20

We move all terms to the left:

-/12z-(27/20)=0



Domain of the equation: 12z!=0

z!=0/12

z!=0

z∈R



We add all the numbers together, and all the variables

-/12z-(+27/20)=0

We get rid of parentheses

-/12z-27/20=0

We calculate fractions


()/240z+(-324z)/240z=0

We multiply all the terms by the denominator


(-324z)+()=0

We add all the numbers together, and all the variables

(-324z)=0

We get rid of parentheses

-324z=0

z=0/-324

z=0

Równanie nie ma rozwiązania

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