-/2(b+2)+3b=-1

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Solution for -/2(b+2)+3b=-1 equation: 



-/2(b+2)+3b=-1

We move all terms to the left:

-/2(b+2)+3b-(-1)=0



Domain of the equation: 2(b+2)!=0

b∈R



We add all the numbers together, and all the variables

3b-/2(b+2)+1=0

We multiply all the terms by the denominator


3b*2(b+2)+1*2(b+2)-=0

We add all the numbers together, and all the variables

3b*2(b+2)+1*2(b+2)=0

Wy multiply elements

6b^2(b+2b(b=0

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