-0,04x2+1.2x-9=0

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Solution for -0,04x2+1.2x-9=0 equation: 



-0.04x^2+1.2x-9=0

a = -0.04; b = 1.2; c = -9;
Δ = b2-4ac
Δ = 1.22-4·(-0.04)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-1.2}{-0.08}=+15$

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