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-0.1x^2+5x+0.6=0
a = -0.1; b = 5; c = +0.6;
Δ = b2-4ac
Δ = 52-4·(-0.1)·0.6
Δ = 25.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{25.24}}{2*-0.1}=\frac{-5-\sqrt{25.24}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{25.24}}{2*-0.1}=\frac{-5+\sqrt{25.24}}{-0.2} $
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