-0.008x2+0.9x+250=0

Solution for -0.008x2+0.9x+250=0 equation:

-0.008x^2+0.9x+250=0

a = -0.008; b = 0.9; c = +250;
Δ = b2-4ac
Δ = 0.92-4·(-0.008)·250
Δ = 8.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.9)-\sqrt{8.81}}{2*-0.008}=\frac{-0.9-\sqrt{8.81}}{-0.016}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.9)+\sqrt{8.81}}{2*-0.008}=\frac{-0.9+\sqrt{8.81}}{-0.016}
$