-0.05x2+x+65=0

Solution for -0.05x2+x+65=0 equation:

-0.05x^2+x+65=0

a = -0.05; b = 1; c = +65;
Δ = b2-4ac
Δ = 12-4·(-0.05)·65
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{14}}{2*-0.05}=\frac{-1-\sqrt{14}}{-0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{14}}{2*-0.05}=\frac{-1+\sqrt{14}}{-0.1}
$